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Sljslj · 07-30-2010, 02:19 AM

I consider myself a fairly intelligent person and seems to me the Monty Hall problem isn't solved in the way everyone says.
So, there's two left, right? One is the car, the other isn't, therefore, you've got a 50% chance of selecting the car. I would think the use of thirds would be eliminated (and replaced with use of halves) once there are only two options. Can someone explain to me why this is wrong?

EDIT: Nvm I get it.

07-30-2010, 02:19 AM	#4 (permalink)
Sljslj The Omniscient Join Date: Mar 2010 Location: Reno, Nevada, USA Posts: 998	I consider myself a fairly intelligent person and seems to me the Monty Hall problem isn't solved in the way everyone says. So, there's two left, right? One is the car, the other isn't, therefore, you've got a 50% chance of selecting the car. I would think the use of thirds would be eliminated (and replaced with use of halves) once there are only two options. Can someone explain to me why this is wrong? EDIT: Nvm I get it. __________________ MY LYRICS